2x^2+36/3=-6x

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Solution for 2x^2+36/3=-6x equation: 


x in (-oo:+oo)

2*x^2+36/3 = -6*x // + -6*x

2*x^2-(-6*x)+36/3 = 0

2*x^2+6*x+36/3 = 0

2*x^2+6*x+12 = 0

DELTA = 6^2-(2*4*12)

DELTA = -60

DELTA < 0

x belongs to the empty set

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